document.write( "Question 178378: Write a system of two equations in two unknowns. Solve each system by substitution.\r
\n" ); document.write( "\n" ); document.write( "The width of a rectangualr painting is two- thirds of its length. If the perimeter is 60in., then what are the length and width? \n" ); document.write( "
Algebra.Com's Answer #133329 by nerdybill(7384)\"\" \"About 
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The width of a rectangualr painting is two- thirds of its length. If the perimeter is 60in., then what are the length and width?
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\n" ); document.write( "Let W = width
\n" ); document.write( "and L = length
\n" ); document.write( "then
\n" ); document.write( "from: \"The width of a rectangualr painting is two- thirds of its length.\"
\n" ); document.write( "W = (2/3)L (equation 1)
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\n" ); document.write( "from: \"the perimeter is 60in\"
\n" ); document.write( "2(W+L) = 60 (equation 2)
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\n" ); document.write( "Substitute the definition of W from equation 1 into equation 2 and solve for L:
\n" ); document.write( "2(W+L) = 60
\n" ); document.write( "2((2/3)L+L) = 60
\n" ); document.write( "2((2/3)L+(3/3)L) = 60
\n" ); document.write( "2((5/3)L) = 60
\n" ); document.write( "(5/3)L = 30
\n" ); document.write( "5L = 90
\n" ); document.write( "L = 18 inches (length)
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\n" ); document.write( "Plug the above into equation 1 and solve for W:
\n" ); document.write( "W = (2/3)L
\n" ); document.write( "W = (2/3)18
\n" ); document.write( "W = (2)6
\n" ); document.write( "W = 12 inches (width) \n" ); document.write( "
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