document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=178365>Question 178365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each system by the substitution method:\r<BR>\n" );
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document.write( "x = -3y + 2<BR>\n" );
document.write( "7y = 3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #133325 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=133325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve each system by the substitution method: <BR>\n" );
document.write( "x = -3y + 2<BR>\n" );
document.write( "7y = 3x<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "x is already given in terms of y in the 1st eqn, so sub into the 2nd.<BR>\n" );
document.write( "7y = 3*(-3y+2)<BR>\n" );
document.write( "7y = -9y+6<BR>\n" );
document.write( "16y = 6<BR>\n" );
document.write( "y = 3/8<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "x = -3y+2<BR>\n" );
document.write( "x = (-9/8)+2<BR>\n" );
document.write( "x = 7/8<BR>\n" );
document.write( " </SPAN>\n" );
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