document.write( "Question 178308: \r
\n" ); document.write( "\n" ); document.write( "Train A and B are traveling in the same direction on parrallel tracks. Train A at 80 miles per hour and train B at 90 miles per hour. Train A passes a station at 7:20pm. If train B passes the same station at 7:32pm, at what time will train B catch up to train A? \r
\n" ); document.write( "\n" ); document.write( "My answer would be N, not defined becuase they are travling at different speeds. However, train B is going faster than train A. If I had to guess, I would say 8:43pm I'm confused, please help me. Thank you for your help!
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Algebra.Com's Answer #133279 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
If the slower train was bhind the faster train,
\n" ); document.write( "the slower train would never catch up.
\n" ); document.write( "This problem puts the faster train behind the slower
\n" ); document.write( "one, so it has a chance to catch up.
\n" ); document.write( "7:32 minus 7:20 is 12 minutes. That's the elapsed
\n" ); document.write( "time between the slower train passing the station
\n" ); document.write( "and the faster train passing it
\n" ); document.write( "How far did the 1st train go in that 12 min?
\n" ); document.write( "12 min is 12/60 of an hour
\n" ); document.write( "\"d+=+r%2At\"
\n" ); document.write( "\"d+=+80%2A%2812%2F60%29\"
\n" ); document.write( "\"d+=+16\"mi
\n" ); document.write( "So, train A has a 16 mi headstart over B
\n" ); document.write( "If I have a stopwatch, and I start it when train B
\n" ); document.write( "passes the station, and I'm also able to stop it
\n" ); document.write( "when B catches A, They'll both be travelling for the
\n" ); document.write( "same length of time, except A is 16 mi closer to
\n" ); document.write( "where they're going to meet.
\n" ); document.write( "For B:
\n" ); document.write( "(1) \"d+=+90t\"
\n" ); document.write( "For A:
\n" ); document.write( "\"d+-+16+=+80t\" (notice \"t\" is the same for both)
\n" ); document.write( "(2) \"d+=+80t+%2B+16\"
\n" ); document.write( "Since both are equal to \"d\", I'll set the
\n" ); document.write( "right sides equal to eachother
\n" ); document.write( "\"90t+=+80t+%2B+16\"
\n" ); document.write( "\"10t+=+16\"
\n" ); document.write( "\"t+=+1.6\"hr
\n" ); document.write( "This is 1 hr + \".6%2A60+=+36\"min
\n" ); document.write( "This is the elapsed time since 7:32 when B passed the station
\n" ); document.write( "7:32 + 1 = 8:32 and 8:32 + 36 min = 9:08
\n" ); document.write( "Train B catches up to train A at 9:08
\n" ); document.write( "I'll check my answer:
\n" ); document.write( "What's the distance from the station to where they meet?
\n" ); document.write( "(1) \"d+=+90t\"
\n" ); document.write( "\"d+=+90%2A1.6\"
\n" ); document.write( "\"d+=+144\"mi
\n" ); document.write( "(2) \"d+=+80t+%2B+16\"
\n" ); document.write( "(2) \"144+=+80t+%2B+16\"
\n" ); document.write( "\"80t+=+144+-+16\"
\n" ); document.write( "\"80t+=+128\"
\n" ); document.write( "\"t+=+1.6\"hr
\n" ); document.write( "OK
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