document.write( "Question 24943: I'm having difficulty figuring out the equation for this word problem from our variable equation unit: \r
\n" ); document.write( "\n" ); document.write( "A truck leaves a rest stop traveling at a steady rate of 56 mph. A car leaves the same rest stop 1/4 hour later, following the truck at a steady rate of 64mph. How long after the truck leaves the rest stop, will the car overtake the truck? Thank you!
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Algebra.Com's Answer #13327 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
First your can simplify 1/4 - 0.25h
\n" ); document.write( "Truck's peed = 56mph
\n" ); document.write( "Cars' speed = 64mph
\n" ); document.write( "After 1/4 hour later with the truck = 56(x+0.25)
\n" ); document.write( "In where x is the distance.
\n" ); document.write( "Car's distance = 64x \r
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\n" ); document.write( "\n" ); document.write( "56(x+0.25)=64x
\n" ); document.write( "56x+14=64x
\n" ); document.write( "simplify
\n" ); document.write( "8x=14
\n" ); document.write( "\"8x%2F8=14%2F8\"
\n" ); document.write( "x=1.75\r
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\n" ); document.write( "\n" ); document.write( "hence it will take the truck 1.75hour to cross the car
\n" ); document.write( "Paul.\r
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