document.write( "Question 178284: A photo is 4 inches longer than it is wide. A 3 inch border is placed around the photo making the total area of the photo and border 165 inches. What are the dimensions of the photo?
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Algebra.Com's Answer #133244 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Length of photo+frame: \"x%2B4%2B6=x%2B10\" Width of photo+frame: \"x%2B6\"\r
\n" ); document.write( "\n" ); document.write( "Area of photo+frame: \"A=%28x%2B10%29%28x%2B6%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=%28x%2B10%29%28x%2B6%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"165=%28x%2B10%29%28x%2B6%29\" Plug in \"A=165\"\r
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\n" ); document.write( "\n" ); document.write( "\"165=x%5E2%2B16x%2B60\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2%2B16x-105\" Subtract 165 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0=%28x%2B21%29%28x-5%29\" Factor\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B21=0\" or \"x-5=0\" Set each factor equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x=-21\" (we'll toss this solution) or \"x=5\" Solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "So the width of the photo is 5 inches which means that the length of the photo is 9 inches (just add 4 to the width).
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