document.write( "Question 178282: I have a word problem that I have worked two diffrent ways and I am still not able to come up with the answer.
\n" ); document.write( "THe problem is:
\n" ); document.write( "A store employee is counting $10.00 and $20.00 bills. If there are 6 times as many $10 bills as $20 bills and the total amount is $1760, find the number of each type of bill. \r
\n" ); document.write( "\n" ); document.write( "10x+60+20x=1760
\n" ); document.write( "30x+60=1760---then subtract 60 from both sides I get
\n" ); document.write( "30x=1700
\n" ); document.write( "x=56.6666666
\n" ); document.write( "I am not sure what I am doing wrong so any help with this would be greatly appreciated!!\r
\n" ); document.write( "\n" ); document.write( "Thanks in Advance.
\n" ); document.write( "

Algebra.Com's Answer #133239 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"a\"= number of $10 bills
\n" ); document.write( "Let \"b\"= number of $20 bills
\n" ); document.write( "given:
\n" ); document.write( "(1) \"a+=+6b\"
\n" ); document.write( "(2) \"10a+%2B+20b+=+1760\"
\n" ); document.write( "Substitute (1) in (2)
\n" ); document.write( "\"10%2A6b+%2B+20b+=+1760\"
\n" ); document.write( "\"80b+=+1760\"
\n" ); document.write( "\"b+=+22\"
\n" ); document.write( "\"a+=+6b\"
\n" ); document.write( "\"a+=+6%2A22\"
\n" ); document.write( "\"a+=+132\"
\n" ); document.write( "There are 132 $10 bills and 22 $20 bills
\n" ); document.write( "check:
\n" ); document.write( "\"10a+%2B+20b+=+1760\"
\n" ); document.write( "\"10%2A132+%2B+20%2A22+=+1760\"
\n" ); document.write( "\"1320+%2B+440+=+1760\"
\n" ); document.write( "\"1760+=+1760\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );