document.write( "Question 178006: Hello, I don't know how to make and equation out of this. - thanks\r
\n" ); document.write( "\n" ); document.write( "Your watch loses 1 1/2 sec every hour. You have a friend whose watch gains 1 second every hour. The watches show the same time now. After how many more seconds will they show the same time again?
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Algebra.Com's Answer #133191 by Alan3354(69443)\"\" \"About 
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Hello, I don't know how to make and equation out of this. - thanks
\n" ); document.write( "Your watch loses 1 1/2 sec every hour. You have a friend whose watch gains 1 second every hour. The watches show the same time now. After how many more seconds will they show the same time again?
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\n" ); document.write( "The times shown are diverging at a rate of 2.5 seconds per hour. They will show the same time again when they are 12 hours apart (assuming it's the common 12 hour display).
\n" ); document.write( "12 hours = 12*60*60 seconds = 43200 seconds
\n" ); document.write( "43200/2.5 = 17,280 seconds
\n" ); document.write( "= 288 minutes
\n" ); document.write( "= 4 hours 48 minutes
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