document.write( "Question 178187: Does this function have a maximum or a minimum? \"x%5E2%2B4x-5=0\" After solving this equation I came up with (x=1) and (x=-5). Am I correct? Please include details. I don't yet know how to find a max or min. Please explain how to find this answer. \n" ); document.write( "
Algebra.Com's Answer #133184 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Given:
\n" ); document.write( "\"x%5E2%2B4x-5=0\"
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\n" ); document.write( "Simply by looking at the coefficient associated with the 'x^2' term (in this case, it's a POSITIVE 1) you can immediately tell that you will find the MINIMUM by finding the \"vertex\" or x-axis of symmetry.
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\n" ); document.write( "A quadratic forms a parabola -- either it is \"open upward\" or \"open downward\". If it is \"open upward\" the vertex is at the minimum. If is \"open downward\" the vertex is at a maximum. If the coefficient (associated with the x^2) is POSITIVE -- it is \"open upward\" (think of it this way, if you're POSITIVE you would have a happy face). If the coefficient is NEGATIVE -- it is \"open downward\" (if you're NEGATIVE, you would be sad faced).
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\n" ); document.write( "The \"vertex form\" is:
\n" ); document.write( "y= a(x-h)^2+k
\n" ); document.write( "where (h,k) is the vertex
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\n" ); document.write( "To find the vertex, complete the square:
\n" ); document.write( "\"x%5E2%2B4x-5\"
\n" ); document.write( "\"%28x%5E2%2B4x%29-5\"
\n" ); document.write( "\"%28x%5E2%2B4x%2B4%29-5-4\"
\n" ); document.write( "\"%28x%5E2%2B4x%2B4%29-9\"
\n" ); document.write( "\"%28x%2B2%29%5E2-9\"
\n" ); document.write( "(h,k) = (-2, -9)
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