document.write( "Question 178179: I replaced the numbers in this equation so I can solve my own numbers. Could someone please help me.
\n" ); document.write( "The medium age of first marriage is 24.5 years in 1995 to 25.1 years in 2000. Let 1995 be year 5 and 2000 be year 10.
\n" ); document.write( "a) Find the equation of the line through (5,24.5)and (10, 25.1).
\n" ); document.write( "b) What do x and y represent in your equation?
\n" ); document.write( "c) Interpret the slope of this line.
\n" ); document.write( "d) In what year will the medium age be 30?
\n" ); document.write( "I want to compare what I have in my problem so please show work. Thank you.
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Algebra.Com's Answer #133138 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The medium age of first marriage is 24.5 years in 1995 to 25.1 years in 2000. Let 1995 be year 5 and 2000 be year 10.
\n" ); document.write( "a) Find the equation of the line through (5,24.5)and (10, 25.1).
\n" ); document.write( "slope = (24.5 - 24.1) / (5 - 10) = 0.4/(-5) = -0.08
\n" ); document.write( "--------------
\n" ); document.write( "intercept: 25.1 = (-0.08)*10 + b
\n" ); document.write( "25.1 = -0.8 + b
\n" ); document.write( "b = 25.9
\n" ); document.write( "---
\n" ); document.write( "Equation: y = -0.08x + 25.9
\n" ); document.write( "------------------------------------\r
\n" ); document.write( "\n" ); document.write( "b) What do x and y represent in your equation?
\n" ); document.write( "x is # of years after 1990
\n" ); document.write( "y is median age of first marriage
\n" ); document.write( "------------------------------------\r
\n" ); document.write( "\n" ); document.write( "c) Interpret the slope of this line.
\n" ); document.write( "As the number of years after 1990 increases by one the median
\n" ); document.write( "age of 1st marriage decreases by 0.08
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\n" ); document.write( "\n" ); document.write( "d) In what year will the medium age be 30?
\n" ); document.write( "30 = -0.08x + 25.9
\n" ); document.write( "-0.08x = 4.1
\n" ); document.write( "x = -51.25
\n" ); document.write( "----
\n" ); document.write( "Year = 1990 -51.25 = 1938.75 or year 1939
\n" ); document.write( "==============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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