document.write( "Question 178160: 44) x/(x^2 – 2x – 3) - 3x/(x^2 – 9) ......please i'm desperate and can you please show the steps, so i can see how u got the answer.\r
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Algebra.Com's Answer #133113 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%2F%28x%5E2-2x-3%29-3x%2F%28x%5E2-9%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F%28%28x%2B1%29%28x-3%29%29-3x%2F%28x%5E2-9%29\" Factor the first denominator\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F%28%28x%2B1%29%28x-3%29%29-3x%2F%28%28x%2B3%29%28x-3%29%29\" Factor the second denominator\r
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\n" ); document.write( "\n" ); document.write( "Take note that the LCD is \"%28x%2B1%29%28x%2B3%29%28x-3%29\" (the LCD is comprised of the unique factors of both denominators). So the goal is to get EVERY denominator equal to the LCD\r
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\n" ); document.write( "\n" ); document.write( " Multiply both the numerator and denominator of the first fraction by \"x%2B3\" to get the denominator equal to the LCD\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B3x%29%2F%28%28x%2B1%29%28x%2B3%29%28x-3%29%29-3x%2F%28%28x%2B3%29%28x-3%29%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( " Multiply both the numerator and denominator of the second fraction by \"x%2B1\" to get the denominator equal to the LCD\r
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\n" ); document.write( "\n" ); document.write( " Distribute\r
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\n" ); document.write( "\n" ); document.write( "Now that EVERY denominator is equal to the LCD, we can subtract the fractions:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B3x-%283x%5E2%2B3x%29%29%2F%28%28x%2B1%29%28x%2B3%29%28x-3%29%29\" Combine the fractions by subtracting the numerators over the common denominator.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B3x-3x%5E2-3x%29%2F%28%28x%2B1%29%28x%2B3%29%28x-3%29%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"%28-2x%5E2%29%2F%28%28x%2B1%29%28x%2B3%29%28x-3%29%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28-2x%5E2%29%2F%28x%5E3%2Bx%5E2-9x-9%29\" Multiply the terms out in the denominator (this step is optional)\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \r
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\n" ); document.write( "\n" ); document.write( " where \"x%3C%3E-3\", \"x%3C%3E-1\", or \"x%3C%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "Or..\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F%28x%5E2-2x-3%29-3x%2F%28x%5E2-9%29=%28-2x%5E2%29%2F%28x%5E3%2Bx%5E2-9x-9%29\" where \"x%3C%3E-3\", \"x%3C%3E-1\", or \"x%3C%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "Note: both answers are the same, but the second one is if you decided to expand the denominator
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