document.write( "Question 178061: A SPEEDBOAT COULD TRAVEL AT 5 TIMES THE SPEED OF A CURRENT. THUS, IT COULD TRAVEL 300 MILES DOWNRIVER IN 2 HOURS MORE THAN IT TOOK TO TRAVEL 150 MILES UPRIVER. WHAT WAS THE SPEED OF THE BOAT IN STILL WATER? \n" ); document.write( "
Algebra.Com's Answer #133101 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A SPEEDBOAT COULD TRAVEL AT 5 TIMES THE SPEED OF A CURRENT. THUS, IT COULD
\n" ); document.write( " TRAVEL 300 MILES DOWNRIVER IN 2 HOURS MORE THAN IT TOOK TO TRAVEL 150 MILES
\n" ); document.write( " UPRIVER. WHAT WAS THE SPEED OF THE BOAT IN STILL WATER?
\n" ); document.write( ";
\n" ); document.write( "let x = boat speed in still water
\n" ); document.write( ":
\n" ); document.write( "given that current speed \"1%2F5\" boat speed, therefore we can say;
\n" ); document.write( ".2x = current speed
\n" ); document.write( ":
\n" ); document.write( "Then
\n" ); document.write( "1.2x = speed down stream
\n" ); document.write( ".8x = speed up stream
\n" ); document.write( ":
\n" ); document.write( "write a time equation time = \"dist%2Fspeed\"
\n" ); document.write( "downstream time = upstream time + 2 hrs
\n" ); document.write( "\"300%2F1.2x\" = \"150%2F.8x\" + 2
\n" ); document.write( "multiply equation by 2.4x to get rid of the denominators
\n" ); document.write( "2(300) = 3(150) + 2(2.4x)
\n" ); document.write( ":
\n" ); document.write( "600 = 450 + 4.8x
\n" ); document.write( ":
\n" ); document.write( "600 - 450 = 4.8x
\n" ); document.write( ":
\n" ); document.write( "x = \"150%2F4.8\"
\n" ); document.write( "x = 31.25 speed of boat in still water
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in original equation
\n" ); document.write( "\"300%2F1.2%2831.25%29\" = \"150%2F.8%2831.25%29\" + 2
\n" ); document.write( "\"300%2F37.5\" = \"150%2F25\" + 2
\n" ); document.write( " 8 = 6 + 2
\n" ); document.write( "
\n" );