document.write( "Question 178061: A SPEEDBOAT COULD TRAVEL AT 5 TIMES THE SPEED OF A CURRENT. THUS, IT COULD TRAVEL 300 MILES DOWNRIVER IN 2 HOURS MORE THAN IT TOOK TO TRAVEL 150 MILES UPRIVER. WHAT WAS THE SPEED OF THE BOAT IN STILL WATER? \n" ); document.write( "
Algebra.Com's Answer #133101 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A SPEEDBOAT COULD TRAVEL AT 5 TIMES THE SPEED OF A CURRENT. THUS, IT COULD \n" ); document.write( " TRAVEL 300 MILES DOWNRIVER IN 2 HOURS MORE THAN IT TOOK TO TRAVEL 150 MILES \n" ); document.write( " UPRIVER. WHAT WAS THE SPEED OF THE BOAT IN STILL WATER? \n" ); document.write( "; \n" ); document.write( "let x = boat speed in still water \n" ); document.write( ": \n" ); document.write( "given that current speed \n" ); document.write( ".2x = current speed \n" ); document.write( ": \n" ); document.write( "Then \n" ); document.write( "1.2x = speed down stream \n" ); document.write( ".8x = speed up stream \n" ); document.write( ": \n" ); document.write( "write a time equation time = \n" ); document.write( "downstream time = upstream time + 2 hrs \n" ); document.write( " \n" ); document.write( "multiply equation by 2.4x to get rid of the denominators \n" ); document.write( "2(300) = 3(150) + 2(2.4x) \n" ); document.write( ": \n" ); document.write( "600 = 450 + 4.8x \n" ); document.write( ": \n" ); document.write( "600 - 450 = 4.8x \n" ); document.write( ": \n" ); document.write( "x = \n" ); document.write( "x = 31.25 speed of boat in still water \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " 8 = 6 + 2 \n" ); document.write( " |