document.write( "Question 177334: ramon is 3 years older than sally. four times ramon's age ten years ago is 5 less than twice ramon's age now. how old are they now? \n" ); document.write( "
Algebra.Com's Answer #133088 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! Let Sally’s age be s \n" ); document.write( "Then Ramon’s age now is s + 3 \n" ); document.write( "Ten years ago, Ramon was s + 3 – 10 = s – 7 \n" ); document.write( "If ten years ago, 4 times Ramon’s age was 5 less than twice his age now, then, 4(s – 7) = 2(s + 3) - 5 \n" ); document.write( " 4s - 28 = 2s + 6 - 5 \n" ); document.write( " 2s = 29 \n" ); document.write( " s = 14.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sally is now 14.5, which means that Ramon is now 17.5 (14.5 + 3).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking: \n" ); document.write( "4(17.5 – 10) = 2(17.5) – 5 \n" ); document.write( "4(7.5) = 35 - 5 \n" ); document.write( "30 = 30 \n" ); document.write( " \n" ); document.write( " |