document.write( "Question 178134: I am stumped! I have been at this math problem for what seems like hours. I would really like it if you can help me out. The answer may be so easy to get, but I just can't figure it out. Please help.\r
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\n" ); document.write( "\n" ); document.write( "The word problem is as followed:\r
\n" ); document.write( "\n" ); document.write( " A computer store sold a total of 300 items last month. The store sold six times as many hard drives as they did CD ROM drives, and half as many floppy drives as hard drives. Based on this information how many of each item was sold?\r
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\n" ); document.write( "\n" ); document.write( "Thanks so much .. your help is greatly appreciated!
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Algebra.Com's Answer #133073 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
let x, y and z be the number of hard drive CD roms, and floppy drive sold, respectively
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\n" ); document.write( "x+y+z=300.......eq 1
\n" ); document.write( "x=6y............eq 2
\n" ); document.write( "z=x/2..........eq 3
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\n" ); document.write( "re write eq 2 to y=x/6. Now take that value of y which is x/6 and z's value from eq 3 which is x/2 and plug them into eq 1
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\n" ); document.write( "x+(x/6)+(x/2)=300
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\n" ); document.write( "6x+x+3x=1800........mulitiplied each term by 6 to get rid of fractions
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\n" ); document.write( "10x=1800
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\n" ); document.write( "\"highlight%28x=180%29\" hard drives sold
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\n" ); document.write( "\"highlight%28y=x%2F6=180%2F6=30%29\"cd roms sold
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\n" ); document.write( "\"highlight%28z=x%2F2=180%2F2=90%29\"floppies sold
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