document.write( "Question 24884: graph 3x+2y=10 plot the points \n" ); document.write( "

Algebra.Com's Answer #13307 by elima(1433) $\"\"$ $\"About$

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You need to put this equation in slope-intercept form;
\n" ); document.write( "y=mx+b
\n" ); document.write( "3x+2y=10
\n" ); document.write( "2y=-3x+10
\n" ); document.write( "y=- $\"3%2F2\"$ x+10
\n" ); document.write( "Now plot the first point, which is given by your equation, where b=y-intercept.
\n" ); document.write( "y-intercept=10
\n" ); document.write( "slope=- $\"3%2F2\"$
\n" ); document.write( "So the first point is (0,10), and with the slope - $\"3%2F2\"$ plot your next point.
\n" ); document.write( "So from that point on the y-axis, go down 3 and over 2, that is point 2.
\n" ); document.write( " $\"graph+%28400%2C400%2C+-12%2C12%2C-4%2C18%2C+%283%2F2%29x%2B10%29\"$
\n" ); document.write( "=) \n" ); document.write( "

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