document.write( "Question 177905: A normally distributed population has a mean of 60 and a standard deviation of 6.\r
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document.write( "Compute the probability of a value between 51 and 66. ________ \r
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document.write( "Compute the probability of a value less than 51. ________ \r
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document.write( "Compute the probability of a value greater than 72. ________ \n" );
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Algebra.Com's Answer #133049 by stanbon(75887) ![]() You can put this solution on YOUR website! A normally distributed population has a mean of 60 and a stand deviation of 6. \n" ); document.write( "------------- \n" ); document.write( "You need to find the z-value on each of these: \n" ); document.write( "For example: \n" ); document.write( "Compute the probability of a value between 51 and 66. ________ \n" ); document.write( "z(66) = (66-60)/6 = 1 \n" ); document.write( "z(51) = (51-60)/6 = -1.5 \n" ); document.write( "P(51 < x < 66) = P(-1.5 < z < 1) = 0.77454.. \n" ); document.write( "----------------------------------------------- \n" ); document.write( " \n" ); document.write( "Compute the probability of a value less than 51. ________ \n" ); document.write( "P(z < 51) = P(z< -1.5) = 0.06681.. \n" ); document.write( "----------------------------------------------- \n" ); document.write( " \n" ); document.write( "Compute the probability of a value greater than 72. ________ \n" ); document.write( "z(72) = (72 - 60)/6 = 12/6 = 2 \n" ); document.write( "P(x > 72) = P(z > 2) = 0.02275... \n" ); document.write( "------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |