document.write( "Question 178081: A person on a bike is going 18 mph.\r
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document.write( "One hour after the person on a bike leaves, a person in a car is going 45 mph.\r
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document.write( "How long will it take for the person in a car to catch up with the bicycle? \n" );
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Algebra.Com's Answer #133039 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! For the bike, \n" ); document.write( "For the car, \n" ); document.write( "When they meet, \n" ); document.write( "given: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So far I have \n" ); document.write( "For the bike, \n" ); document.write( "For the car, \n" ); document.write( "Since they're both equal to \n" ); document.write( " \n" ); document.write( "Suppose I have a stopwatch and I start it when the car leaves \n" ); document.write( "and I know that the bike left 1 hour ago \n" ); document.write( "I can say \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That's 1 hr and 40 min \n" ); document.write( "Since the bike had a 1 hr headstart, the car took 40 min \n" ); document.write( "to catch the bike \n" ); document.write( "check answer: \n" ); document.write( "For the bike, \n" ); document.write( "For the car, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The distance should be the same for both and it is \n" ); document.write( " \n" ); document.write( " |