document.write( "Question 178081: A person on a bike is going 18 mph.\r
\n" ); document.write( "\n" ); document.write( "One hour after the person on a bike leaves, a person in a car is going 45 mph.\r
\n" ); document.write( "\n" ); document.write( "How long will it take for the person in a car to catch up with the bicycle?
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Algebra.Com's Answer #133039 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
For the bike, \"d%5Bb%5D+=+r%5Bb%5D%2At%5Bb%5D\"
\n" ); document.write( "For the car, \"d%5Bc%5D+=+r%5Bc%5D%2At%5Bc%5D\"
\n" ); document.write( "When they meet, \"d%5Bb%5D+=+d%5Bc%5D\", so I'll just call it \"d\"
\n" ); document.write( "given:
\n" ); document.write( "\"r%5Bb%5D+=+18\" mi/hr
\n" ); document.write( "\"r%5Bc%5D+=+45\" mi/hr
\n" ); document.write( "So far I have
\n" ); document.write( "For the bike, \"d+=+18%2At%5Bb%5D\"
\n" ); document.write( "For the car, \"d+=+45%2At%5Bc%5D\"
\n" ); document.write( "Since they're both equal to \"d\", I can say
\n" ); document.write( "\"18%2At%5Bb%5D+=+45%2At%5Bc%5D\"
\n" ); document.write( "Suppose I have a stopwatch and I start it when the car leaves
\n" ); document.write( "and I know that the bike left 1 hour ago
\n" ); document.write( "I can say \"t%5Bc%5D+=+t%5Bb%5D+-+1\"
\n" ); document.write( "\"18%2At%5Bb%5D+=+45%2A%28t%5Bb%5D+-+1%29\"
\n" ); document.write( "\"18%2At%5Bb%5D+=+45t%5Bb%5D+-+45\"
\n" ); document.write( "\"27t%5Bb%5D+=+45\"
\n" ); document.write( "\"t%5Bb%5D+=+5%2F3\"hr , or in minutes
\n" ); document.write( "\"t%5Bb%5D+=+%285%2F3%29%2A60\"
\n" ); document.write( "\"%285%2F3%29%2A60+=+100\" min
\n" ); document.write( "That's 1 hr and 40 min
\n" ); document.write( "Since the bike had a 1 hr headstart, the car took 40 min
\n" ); document.write( "to catch the bike
\n" ); document.write( "check answer:
\n" ); document.write( "For the bike, \"d+=+18%2At%5Bb%5D\"
\n" ); document.write( "For the car, \"d+=+45%2At%5Bc%5D\"
\n" ); document.write( "\"d+=+18%2A%285%2F3%29\"
\n" ); document.write( "\"d+=+30\"
\n" ); document.write( "\"d+=+45%2A%282%2F3%29\"
\n" ); document.write( "\"d+=+15%2A2\"
\n" ); document.write( "\"d+=+30\"
\n" ); document.write( "The distance should be the same for both and it is
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