document.write( "Question 177904: From experience, a battery manufacturer knows the probability of a battery being defective is .08. If a retail customer buys four batteries, what is the probability that none of the batteries are defective? ___________ \n" ); document.write( "
Algebra.Com's Answer #132949 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Battery quality is an independent event, probabilities multiply. \n" ); document.write( "Probability of 1 defect free battery = 1-0.08=0.92 \n" ); document.write( "Probability of 2 defect free batteries= 0.92*0.92=0.846. \n" ); document.write( "Probability of 3 defect free batteries= 0.92*0.92*0.92=0.779. \n" ); document.write( "Probability of 4 defect free batteries= 0.92*0.92*0.92*0.92=0.716. \n" ); document.write( "The probability is 71.6% that you'll have 4 defect free batteries. \n" ); document.write( " \n" ); document.write( " |