document.write( "Question 177948: My question is Find the length and width of a rectangular lot with a perimeter of 70 meters if the length is 5 meters more than the width. \n" ); document.write( "
Algebra.Com's Answer #132905 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let W=width and L=length\r
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\n" ); document.write( "\n" ); document.write( "Since the \"length is 5 meters more than the width\", this tells us that \"L=W%2B5\" (ie add 5 to the width to get the length)\r
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\n" ); document.write( "\n" ); document.write( "\"P=2L%2B2W\" Start with the perimeter formula\r
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\n" ); document.write( "\n" ); document.write( "\"70=2%28W%2B5%29%2B2W\" Plug in \"P=70\" (the given perimeter) and \"L=W%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "\"70=2W%2B10%2B2W\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"70-10=2W%2B2W\" Subtract 10 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"60=4W\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"60%2F4=W\" Divide both sides by 4 to isolate \"W\"\r
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\n" ); document.write( "\n" ); document.write( "\"15=W\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the width is 15 meters\r
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\n" ); document.write( "\n" ); document.write( "\"L=W%2B5\" Go back to the length equation\r
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\n" ); document.write( "\n" ); document.write( "\"L=15%2B5\" Plug in \"W=15\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=20\" Add\r
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\n" ); document.write( "\n" ); document.write( "So the length is 20 meters.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the length is 20 meters and the width is 15 meters
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