document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24818>Question 24818</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I REALLY NEED THE ANSWER IN DETAIL TO THIS PROBLEM..ITS DUE TOMORROW and its very important. THANK YOU\r<BR>\n" );
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document.write( "* A window in a bulinging is 18m above the ground. From this window, the angle of elevation to the top of the building across the street is 40° and the angle of depression to the bottom of the building acress the street is 42°. How tall is the building across the street? Include a labelled diagram with you solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13290 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A window in a bulinging is 18m above the ground. From this window, the angle of elevation to the top of the building across the street is 40° and the angle of depression to the bottom of the building acress the street is 42°. How tall is the building across the street? Include a labelled diagram with you solution<BR>\n" );
document.write( "I AM GIVING A GRAPH BELOW FOR YOUR GUIDANCE.YOU CAN COMPLETE THE DRAWING AND LABEL THE DIAGRAM ON THE BASIS GIVEN BELOW.<BR>\n" );
document.write( "LET O BE THE ORIGIN;LET THE Y AXIS BE THE BUILDING , THE WINDOW AT 18M.ABOVE GROUND BE ON THE Y AXIS AT W ; AND X AXIS THE GROUND.<BR>\n" );
document.write( "HENCE OW = 18 M.<BR>\n" );
document.write( " THE LINE OF ELEVATION OF TOP OF THE BUILDIND ACROSS THE STREET FROM WINDOW ON Y AXIS IS SHOWN BY WT;AND THE LINE OF DEPRESSION OF THE BUILDING FROM THIS WINDOW IS SHOWN BY WB.JOIN BT WHICH WILL BE PERPENDICULAR TO THE GROUND OR X AXIS.DRAW A HORIZONTAL W H FROM WIDOW W TO BUILDING LINE BT.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+600%2C+600%2C+0%2C+10%2C+0%2C+10%2C+x%2B4%2C4-x%2C4%29+ ALIGN=MIDDLE  ALT=\"+graph%28+600%2C+600%2C+0%2C+10%2C+0%2C+10%2C+x%2B4%2C4-x%2C4%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "WE HAVE 2 RIGHT ANGLE TRIANGLES WTH AND WHB.IN TRIANGLE WTH<BR>\n" );
document.write( "ANGLE TWH = 40 DEGREES THE ANGLE OF ELEVATION<BR>\n" );
document.write( "HENCE TAN 40 = TH/WH  OR TH =WH * TAN 40.............I<BR>\n" );
document.write( "IN TRIANGLE WHB <BR>\n" );
document.write( "ANGLE HWB = 42 DEGREES THE ANGLE OF DEPRESSION.<BR>\n" );
document.write( "HENCE TAN 42 = HB/WH  OR  WH=HB/TAN 42<BR>\n" );
document.write( "BUT HB = OW =18 M ..SO..WH=18 /TAN 42.................II<BR>\n" );
document.write( "SUBSTITUTING IN EQN.I WE GET <BR>\n" );
document.write( "TH = 18*TAN 40 / TAN 42<BR>\n" );
document.write( "SO HEIGHT OF BUILDING = TH +HB =18*TAN 40 / TAN 42 +18<BR>\n" );
document.write( "=18*{(TAN 40 / TAN 42 ) + 1 }..YOU CAN SUBSTITUTE THE VALUES FOR TAN 40  AN TAN 42 AND GET THE HEIGHT AS 34.77 M. <BR>\n" );
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