document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177756>Question 177756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Linear System<BR>\n" );
document.write( "Solve each linear system using the method of substitution.<BR>\n" );
document.write( "a) y=6-3x<BR>\n" );
document.write( "   y=2x+1\r<BR>\n" );
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document.write( "b) 5x-y=4<BR>\n" );
document.write( "   3x+y=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132889 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132889\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y  =  6  -  3x <BR>\n" );
document.write( "Y  =  2x  +  1<BR>\n" );
document.write( "Substitute the y-value in eq (i) into eq (ii). This gives us:<BR>\n" );
document.write( "6   -   3x   =   2x   +   1<BR>\n" );
document.write( "- 5x   =   - 5<BR>\n" );
document.write( "x   =   1\r<BR>\n" );
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document.write( "Substitute this x-value in eq (ii), we get: y  =  2(1) + 1<BR>\n" );
document.write( "Y  =  3\r<BR>\n" );
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document.write( "Answer – (1, 3)\r<BR>\n" );
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document.write( "You should now be able to do the next one. Good luck!! </SPAN>\n" );
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