document.write( "Question 177856: Write each function in vertex form. Sketch the graph of the function and
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document.write( "label its vertex.\r
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document.write( "33. y = x2 + 4x - 7
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document.write( "34. y = -x2 + 4x - 1
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document.write( "35. y = 3x2 + 18x
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document.write( "36.y = 1/2x2 - 5x + 12 \n" );
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Algebra.Com's Answer #132877 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Write each function in vertex form. Sketch the graph of the function and \n" ); document.write( "label its vertex. \r \n" ); document.write( "\n" ); document.write( "33. y = x^2 + 4x - 7 \n" ); document.write( "x^2 + 4x + ? = y+7+? \n" ); document.write( "x^2 + 4x + 4 = y+7+4 \n" ); document.write( "(x+2)^2 = y + 11 \n" ); document.write( "----------------- \n" ); document.write( "Vertex: (-2,-11) \n" ); document.write( " \n" ); document.write( "================================================== \n" ); document.write( " \n" ); document.write( "34. y = -x^2 + 4x - 1 \n" ); document.write( "35. y = 3x^2 + 18x \n" ); document.write( "------------------------- \n" ); document.write( "36.y = 1/2x^2 - 5x + 12 \n" ); document.write( "(1/2)x^2 - 5x + ? = y-12 + ? \n" ); document.write( "(1/2)[x^2 - 10x + ? = y-12 + ? \n" ); document.write( "(1/2)[x^2 - 10x + 25] = y - 12 + (1/2)*25 \n" ); document.write( "(1/2)[x-5]^2 = y + (1/2) \n" ); document.write( "---- \n" ); document.write( "Vertex: (5,-1/2)) \n" ); document.write( " \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |