document.write( "Question 177887: A coin bank contains only qurarters and dimes. The total value of the coins is $10.40. If the dimes were quarters and the quarters were dimes the total value of the coins would be $9.20. Find the total number of dimes in the bank. \n" ); document.write( "
Algebra.Com's Answer #132870 by nerdybill(7384)\"\" \"About 
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Let d = dimes
\n" ); document.write( "and q = quarters
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\n" ); document.write( "Since we have two unknowns we'll need two equations.
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\n" ); document.write( "From: \"The total value of the coins is $10.40.\"
\n" ); document.write( ".10d + .25q = 10.40 (equation 1)
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\n" ); document.write( "From: \"If the dimes were quarters and the quarters were dimes the total value of the coins would be $9.20\"
\n" ); document.write( ".25d + .10q = 9.20 (equation 2)
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\n" ); document.write( "Using Cramer's rule:
\n" ); document.write( "Determinant of coefficients:
\n" ); document.write( "(.10)(.10)-(.25)(.25)
\n" ); document.write( "=(0.01)-(0.0625)
\n" ); document.write( "=-0.0525
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\n" ); document.write( "Determinant of d:
\n" ); document.write( "(10.40)(.10)-(9.20)(.25)
\n" ); document.write( "=(1.04)-(2.3)
\n" ); document.write( "=-1.26
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\n" ); document.write( "Determinant of q:
\n" ); document.write( "(.10)(9.20)-(.25)(10.40)
\n" ); document.write( "=(.10)(9.20)-(.25)(10.40)
\n" ); document.write( "=(.92)-(2.6)
\n" ); document.write( "= -1.68
\n" ); document.write( ".
\n" ); document.write( "d = Detd/DetCoeff
\n" ); document.write( "d = -1.26/-0.0525
\n" ); document.write( "d = 24 (number of dimes)
\n" ); document.write( ".
\n" ); document.write( "q = Detq/DetCoeff
\n" ); document.write( "q = -1.68/-0.0525
\n" ); document.write( "q = 32 (number of quarters)
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