document.write( "Question 177887: A coin bank contains only qurarters and dimes. The total value of the coins is $10.40. If the dimes were quarters and the quarters were dimes the total value of the coins would be $9.20. Find the total number of dimes in the bank. \n" ); document.write( "
Algebra.Com's Answer #132870 by nerdybill(7384) You can put this solution on YOUR website! Let d = dimes \n" ); document.write( "and q = quarters \n" ); document.write( ". \n" ); document.write( "Since we have two unknowns we'll need two equations. \n" ); document.write( ". \n" ); document.write( "From: \"The total value of the coins is $10.40.\" \n" ); document.write( ".10d + .25q = 10.40 (equation 1) \n" ); document.write( ". \n" ); document.write( "From: \"If the dimes were quarters and the quarters were dimes the total value of the coins would be $9.20\" \n" ); document.write( ".25d + .10q = 9.20 (equation 2) \n" ); document.write( ". \n" ); document.write( "Using Cramer's rule: \n" ); document.write( "Determinant of coefficients: \n" ); document.write( "(.10)(.10)-(.25)(.25) \n" ); document.write( "=(0.01)-(0.0625) \n" ); document.write( "=-0.0525 \n" ); document.write( ". \n" ); document.write( "Determinant of d: \n" ); document.write( "(10.40)(.10)-(9.20)(.25) \n" ); document.write( "=(1.04)-(2.3) \n" ); document.write( "=-1.26 \n" ); document.write( ". \n" ); document.write( "Determinant of q: \n" ); document.write( "(.10)(9.20)-(.25)(10.40) \n" ); document.write( "=(.10)(9.20)-(.25)(10.40) \n" ); document.write( "=(.92)-(2.6) \n" ); document.write( "= -1.68 \n" ); document.write( ". \n" ); document.write( "d = Detd/DetCoeff \n" ); document.write( "d = -1.26/-0.0525 \n" ); document.write( "d = 24 (number of dimes) \n" ); document.write( ". \n" ); document.write( "q = Detq/DetCoeff \n" ); document.write( "q = -1.68/-0.0525 \n" ); document.write( "q = 32 (number of quarters) \n" ); document.write( " |