document.write( "Question 177873: If the complement of an angle is 5degrees less than one-sixth of its supplement. Find the measure of the angle. \n" ); document.write( "
Algebra.Com's Answer #132845 by stanbon(75887)\"\" \"About 
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If the complement of an angle is 5degrees less than one-sixth of its supplement. Find the measure of the angle.
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\n" ); document.write( "Let the angle be \"x\".
\n" ); document.write( "Its complement = \"90-x\"
\n" ); document.write( "Its supplement = \"180-x\"
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\n" ); document.write( "Equation:
\n" ); document.write( "90-x = (1/6)(180-x)-5\r
\n" ); document.write( "\n" ); document.write( "90-x = 30 - x/6 - 5\r
\n" ); document.write( "\n" ); document.write( "90 - x = 25 - x/6\r
\n" ); document.write( "\n" ); document.write( "65 = (5/6)x\r
\n" ); document.write( "\n" ); document.write( "x = (6/5)*65\r
\n" ); document.write( "\n" ); document.write( "x = 6*13\r
\n" ); document.write( "\n" ); document.write( "x = 78 Degrees (measure of the angle)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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