document.write( "Question 177806: Quadratic Relations
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document.write( "A basketball shot is taken from a horizontal distance of 5m from the hoop. The height of the ball can be modelled by the relation h=-7.3t^2+8.25t+2.1, where h is the height, in metres, and t is the time, in seconds, since the ball was released.
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document.write( "a) From what height was the ball released?
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document.write( "b) What was the maximum height reached by the ball?
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document.write( "c) If the ball reached the hoop in 1 s, what was the height of the hoop? \n" );
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Algebra.Com's Answer #132844 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A basketball shot is taken from a horizontal distance of 5m from the hoop. The height of the ball can be modelled by the relation h=-7.3t^2+8.25t+2.1, where h is the height, in metres, and t is the time, in seconds, since the ball was released. \n" ); document.write( ": \n" ); document.write( "a) From what height was the ball released? \n" ); document.write( "Released when t = 0, therefore -7.3(0^2) + 8.25(0) + 2.1 = 2.1 meters \n" ); document.write( ": \n" ); document.write( "b) What was the maximum height reached by the ball? \n" ); document.write( "Max height occurs at the axis of symmetry, x = -b/(2a; in this equation we have: \n" ); document.write( "t = \n" ); document.write( "t = .565 sec \n" ); document.write( "Max height = -7.3(.565^2) + 8.25(.565) + 2.1, \n" ); document.write( "h = -2.33 + 4.66 + 2.1 \n" ); document.write( "h = 4.43 meters max height \n" ); document.write( ": \n" ); document.write( "c) If the ball reached the hoop in 1 s, what was the height of the hoop? \n" ); document.write( "Substitute 1 for t, find h \n" ); document.write( "h =-7.3(1^2) + 8.25(1) + 2.1 \n" ); document.write( "h =-7.3 + 8.25 + 2.1 \n" ); document.write( "h = 3.05 meters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |