document.write( "Question 177861: If a pro-basketball player has a vertical leap of 35 in, what is his hang time? Use the hang time function of V=48T^2.
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document.write( "Hang time in seconds.
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document.write( "Please help, thank you. \n" );
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Algebra.Com's Answer #132833 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( "V=48T^2 \n" ); document.write( "where \n" ); document.write( "V is vertical leap \n" ); document.write( "T is time (in seconds) \n" ); document.write( ". \n" ); document.write( "Plugging in the given vertical leap: \n" ); document.write( "V=48T^2 \n" ); document.write( "35=48T^2 \n" ); document.write( "35/48 = T^2 \n" ); document.write( "0.72917 = T^2 \n" ); document.write( "Taking the square root of both sides: \n" ); document.write( "0.854 secs = T \n" ); document.write( " |