document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177850>Question 177850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the additive inverse of each number. (please)\r<BR>\n" );
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document.write( "15. -2 - 3i \r<BR>\n" );
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document.write( "16. 1 + 4i\r<BR>\n" );
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document.write( "17. 5 - 3i \r<BR>\n" );
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document.write( "18. -7 + 2i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132830 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when additive inverses are added together they will equal 0+0i<BR>\n" );
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document.write( "so I will do the first 2<BR>\n" );
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document.write( "15. -2 - 3i....additive inverse--->2+3i<BR>\n" );
document.write( "16. 1 + 4i.....additive inverse -->-1-4i  </SPAN>\n" );
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