document.write( "Question 177767: Please solve \r
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Algebra.Com's Answer #132796 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "A. \r
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\n" ); document.write( "\n" ); document.write( " Step 1: Expand the binomial on the left:\r
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\n" ); document.write( "\n" ); document.write( "Step 2: A simple substitution will allow us to deal with this ugliness in a fairly straightforward manner.\r
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\n" ); document.write( "\n" ); document.write( "Let , then:\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Put the quadratic into standard form:\r
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\n" ); document.write( "\n" ); document.write( "Giving us a factorable quadratic in t, so:\r
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\n" ); document.write( "\n" ); document.write( "Step 4: Factor the quadratic:\r
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\n" ); document.write( "\n" ); document.write( "Therefore or \r
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\n" ); document.write( "\n" ); document.write( "But we aren't done yet.\r
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\n" ); document.write( "\n" ); document.write( "Step 5: Since ,\r
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\n" ); document.write( "\n" ); document.write( "But we are still not done.\r
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\n" ); document.write( "\n" ); document.write( "Step 6: Check the potential roots to ensure that we have not introduced extraneous roots in the process of solving the problem:\r
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\n" ); document.write( "\n" ); document.write( "If then,
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\n" ); document.write( "\n" ); document.write( "Now we are done.\r
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\n" ); document.write( "\n" ); document.write( "B. \r
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\n" ); document.write( "\n" ); document.write( "Step 1: Add -3 to both sides and then multiply by to obtain:\r
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\n" ); document.write( "\n" ); document.write( "Step 2: Square both sides:\r
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\n" ); document.write( "\n" ); document.write( "Step 3: Add -1 to both sides and then multiply by to obtain:\r
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\n" ); document.write( "\n" ); document.write( "Step 4: Take the square root of both sides, considering both the positive and negative roots, and then rationalize the denominators:\r
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\n" ); document.write( "\n" ); document.write( "Step 5: Check the potential solutions.\r
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\n" ); document.write( "\n" ); document.write( "Since regardless of whether or , if one solution is good, then they both are:\r
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\n" ); document.write( "\n" ); document.write( "True statement, both potential solutions confirmed.
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