document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177778>Question 177778</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many bushels from a mixture that is 1/3 oats must be added to 480 bushels of a mixture that is 75% corn to get a mixture that will be 70% corn? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132778 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many bushels from a mixture that is 1/3 oats must be added to 480 bushels of a mixture that is 75% corn to get a mixture that will be 70% corn?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "corn + corn = corn<BR>\n" );
document.write( "(2/3)x + 0.75(480) = 0.70(480+x)<BR>\n" );
document.write( "(2/3)x + 360 = 336 + 0.7x<BR>\n" );
document.write( "24 = 0.3333x<BR>\n" );
document.write( "x = 72 bushels (# of bushels containing 1/3 corn that must be in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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