document.write( "Question 177760: Linear System
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document.write( "Solve by elimination. Check each solution.
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document.write( "a) 2a+b=5
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document.write( " a-2b=10\r
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document.write( "b) 4k+3h=12
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document.write( " 4k-h=4
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Algebra.Com's Answer #132770 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! I'll do the first one of these and you can repeat the process for the other one.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 1: Multiply Eq. 1 by 2 so that the coefficients on the b terms are additive inverses (one is already -2 and the other becomes 2):\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation 3: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 2: Add Eq 3 to Eq 2, term by term, eliminating the b variable (hence the name of the method)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation 4: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Step 3: Substitute the value determined for a into either of the original equations and then solve for b:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the solution set for the system:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "is the ordered pair \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking the answer is left as an exercise for the student. \n" ); document.write( " \n" ); document.write( " |