document.write( "Question 177697: what is the solution of 1/x+2/y=9;7/x+11/y=54? \n" ); document.write( "
Algebra.Com's Answer #132757 by ankor@dixie-net.com(22740)\"\" \"About 
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\"1%2Fx\" + \"2%2Fy\" = 9
\n" ); document.write( "\"7%2Fx\" + \"11%2Fy\" = 54
\n" ); document.write( ":
\n" ); document.write( "multiply both equations by xy, results:
\n" ); document.write( "y + 2x = 9xy
\n" ); document.write( "7y + 11x = 54xy
\n" ); document.write( ":
\n" ); document.write( "multiply the 1st equation by 7, subtract the 2nd equation from it
\n" ); document.write( "7y + 14x = 63xy
\n" ); document.write( "7y + 11x = 54xy
\n" ); document.write( "------------------
\n" ); document.write( "0 + 3x = 9xy
\n" ); document.write( "Divide both sides by 3x:
\n" ); document.write( "1 = 3y
\n" ); document.write( "y = \"1%2F3\"
\n" ); document.write( ":
\n" ); document.write( "find x
\n" ); document.write( "y + 2x = 9xy
\n" ); document.write( "\"1%2F3\" + 2x = \"1%2F3\"*9x
\n" ); document.write( "\"1%2F3\" + 2x = 3x
\n" ); document.write( "\"1%2F3\" = 3x - 2x
\n" ); document.write( "x = \"1%2F3\"
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "check solution
\n" ); document.write( "\"7%2Fx\" + \"11%2Fy\" = 54
\n" ); document.write( "substitute 1/3 for x and y
\n" ); document.write( "(3*7) + (3*11) = 54\r
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