document.write( "Question 177738: what is the solution for C(x)=1.5x/100-x \n" ); document.write( "
Algebra.Com's Answer #132747 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"C%28x%29=1.5x%2F%28100-x%29\" Start with the given function.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0=1.5x%2F%28100-x%29\" Plug in \"C%28x%29=0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0%28100-x%29=1.5x\" Multiply both sides by \"100-x\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0=1.5x\" Multiply and simplify. So what really counts is the numerator.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0%2F1.5=x\" Divide both sides by 1.5\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0=x\" Divide\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the answer is \"x=0\"
\n" ); document.write( "
\n" );