document.write( "Question 177735: can you show me the steps it takes to use Hero's formula for the area of a triangle
\n" ); document.write( "A=(square root..did not know how to put this symbol in)s(s-a)(s-b)(s-c)
\n" ); document.write( "if a=5in.,b=12in.,c=5in., and s=6in.
\n" ); document.write( "I don't understand the steps used in solving this problem.....thanks
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Algebra.Com's Answer #132744 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"A=sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29\" Start with Hero's formula\r
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\n" ); document.write( "\n" ); document.write( "\"A=sqrt%286%286-5%29%286-12%29%286-5%29%29\" Plug in \"a=5\", \"b=12\", \"c=5\" and \"s=6\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=sqrt%286%281%29%28-6%29%281%29%29\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"A=sqrt%28-36%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Since you CANNOT take the square root of a negative number, this means that a triangle CANNOT be formed given side lengths of 5, 12, and 5 inches. So double check the problem.
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