document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177728>Question 177728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -(1/6)xy + (-2/3)xy = (   ?    )xy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132722 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -(1/6)xy + (-2/3)xy = (   ?    )xy.........remember -2/3 is also -4/6...so now we have a common denominator and can add like terms<BR>\n" );
document.write( ":<BR>\n" );
document.write( "(-1/6)xy-(4/6)xy=(-5/6)xy </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );