document.write( "Question 177700: I know there is a simpler way of doing this problem other than replacing the variable with each consecutive integer until they add up to 300, because I tried that and they didn't add up. I would appreciate any help with this problem.
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document.write( "\"The sum of the consecutive integers 1,2,3, ..., n is given by the formula . How many consecutive integers, starting with 1, must be added to get a sum of 300?\" \n" );
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Algebra.Com's Answer #132703 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! you just set the equation to 300 and solve for n as follows: \n" ); document.write( "n*(n+1)/2 = 300 \n" ); document.write( "(n^2 + n)/2 = 300 \n" ); document.write( "multiply both sides by 2 to get: \n" ); document.write( "n^2 + n = 600 \n" ); document.write( "subtract 600 from both sides to get: \n" ); document.write( "n^2 + n - 600 = 0 \n" ); document.write( "this is a quadratic equation. \n" ); document.write( "factor to get: \n" ); document.write( "(n+25) * (n-24) = 0 \n" ); document.write( "n = -25 \n" ); document.write( "or \n" ); document.write( "n = 24 \n" ); document.write( "since n has to be positive, the only answer can be n = 24 \n" ); document.write( "substitute in original equation to get: \n" ); document.write( "n * (n + 1)/2 = 300 \n" ); document.write( "which becomes: \n" ); document.write( "(24*25)/2 = 300 \n" ); document.write( "which becomes: \n" ); document.write( "600/2 = 300 \n" ); document.write( "which becomes: \n" ); document.write( "300 = 300 \n" ); document.write( "equation is true so the value of n = 24 is good. \n" ); document.write( "your answer is: \n" ); document.write( "the number of consecutive integers, starting with 1, added together to get a sum of 300, is 24. \n" ); document.write( "--- \n" ); document.write( " \n" ); document.write( " |