document.write( "Question 177699: I would appreciate any help on this problem, I've made up a table for this problem as the teacher had shown in class for other similar examples but my answer doesn't seem to check out.
\n" ); document.write( "\"A Laboratory has 60 mL of a solution that is 40% HCl acid. How many mL of 15% HCL acid solution should be mixed with the 60 mL of 40% acid to obtain a solution of 25% HCl?\"
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Algebra.Com's Answer #132702 by stanbon(75887)\"\" \"About 
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A Laboratory has 60 mL of a solution that is 40% HCl acid. How many mL of 15% HCL acid solution should be mixed with the 60 mL of 40% acid to obtain a solution of 25% HCl
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\n" ); document.write( "Active ingredient Equation:
\n" ); document.write( "0.40*60 + 0.15x = 0.25(x+60)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "40*60 + 15x = 25x + 25*60
\n" ); document.write( "10 x = 15*60
\n" ); document.write( "x = 90 mL (amt. of 15% solution that must be added to the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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