document.write( "Question 177701: At 9:00 a.m. a truck leaves the truck yard and travels west at a rate of 45 mi/hr. Two hours later, a second truck leaves along the same route, traveling at 55 mi/hr. When will the second truck catch up to the first? \n" ); document.write( "
Algebra.Com's Answer #132696 by kollanag(3)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "1st truck travels at s1 = u1 + v1t1 \n" ); document.write( "for 2nd truck s2 = u2+ v2t2\r \n" ); document.write( "\n" ); document.write( "t1 = t2 + 2\r \n" ); document.write( "\n" ); document.write( "s1 = s2\r \n" ); document.write( "\n" ); document.write( "u1 and u2 are zeros.\r \n" ); document.write( "\n" ); document.write( "so\r \n" ); document.write( "\n" ); document.write( "45t1 = 55t1 - 110\r \n" ); document.write( "\n" ); document.write( "==> t1 = 11 hr.\r \n" ); document.write( "\n" ); document.write( "so at the time of 8 PM they will meet. \n" ); document.write( " |