document.write( "Question 24855: how can i solve this problem????\r
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document.write( "the length of a rectangle is 2 cm more than four times the width if the perimeter of the rectangle is 24 cm what are its dimensions? \n" );
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Algebra.Com's Answer #13268 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = width of the rectangle \n" ); document.write( "4x+2 = length of the rectangle\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 W + 2 L = P \n" ); document.write( "2(x) + 2(4x+2) = 24 \n" ); document.write( "2x + 8x + 4 = 24 \n" ); document.write( "10x = 20 \n" ); document.write( "x= 2 cm = width \n" ); document.write( "4x +2 =4(2) + 2 = 10 cm = length\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "2 W + 2 L = 24 \n" ); document.write( "2(2) + 2(10) = 24 \n" ); document.write( "4 + 20 = 24\r \n" ); document.write( "\n" ); document.write( "It checks!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |