document.write( "Question 177629: To strengthen a mixture of 10% alcohol to 30% alcohol, how much pur alcohol must be added to 7 L of the 10% solution? Can you how me step by step \n" ); document.write( "
Algebra.Com's Answer #132659 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! let x be the amount of pure alcohol added \n" ); document.write( ": \n" ); document.write( "existing solution+added solution=final mixture \n" ); document.write( ": \n" ); document.write( ".10(7)=existing \n" ); document.write( ": \n" ); document.write( "x = pure alcohol added \n" ); document.write( ": \n" ); document.write( ".3(7+x)=final mixture(see we want to end up with 30% of what we are mixing and thats the original 7 liters plus what ever we add. \n" ); document.write( ": \n" ); document.write( "so putting it altogether we have \n" ); document.write( ": \n" ); document.write( ".10(7)+x=.3(7+x).....eq 1 \n" ); document.write( ": \n" ); document.write( ".7+x=2.1+.3x \n" ); document.write( ": \n" ); document.write( ".7x=1.4 \n" ); document.write( ": \n" ); document.write( " |