document.write( "Question 177494: Hermin is 6 years older than Doy. Eight years from now, Hermin will be 4 times as old as Doy was 4 years ago. Find their present ages? \n" ); document.write( "
Algebra.Com's Answer #132609 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=Doy's present age; x+8=Doy's age 8 years from now; x-4=Doy's age 4 years ago \n" ); document.write( "Then x+6=Hermin's present age; x+14=Hermin's age 8 years from now\r \n" ); document.write( "\n" ); document.write( "Now we are told the following: \n" ); document.write( "x+14=4(x-4) get rid of parens (distributive) \n" ); document.write( "x+14=4x-16 subtract x from and add 16 to each side \n" ); document.write( "x-x+14+16=4x-x-16+16 collect like terms \n" ); document.write( "30=3x divide each side by 3 \n" ); document.write( "x=10-----------------------Doy's present age \n" ); document.write( "x+6=10+6=16 ----------------Hermin's present age\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "16+8=4(10-4) \n" ); document.write( "24=24\r \n" ); document.write( "\n" ); document.write( "Does this help???----------------ptaylor \n" ); document.write( " |