document.write( "Question 177577: The perimeter of a rectangular yard is 290 feet. If its length is 25 feet greater than its width, what are the dimensions of the yard. Use the five step method to solve. \n" ); document.write( "

Algebra.Com's Answer #132607 by Mathtut(3670) $\"\"$ $\"About$

You can put this solution on YOUR website!
again I will leave the 5-steps to you
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\n" ); document.write( "P=2L+2W...eq 1
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\n" ); document.write( "L=W+25....eq 2
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\n" ); document.write( "P=290.....eq 3
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\n" ); document.write( "take values of eq 2 and 3 and plug them into eq 1
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\n" ); document.write( "290=2(W+25)+2W
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\n" ); document.write( "290=2W+50+2W......distributed right side
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\n" ); document.write( "240=4W
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\n" ); document.write( " $\"highlight%28W=60%29\"$ feet
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\n" ); document.write( " $\"L=W%2B25=60%2B25=highlight%2885%29\"$ feet
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\n" ); document.write( "Yard is 60x85
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