document.write( "Question 177529: A 16-quart radiator contains a 50% solution of antifreeze. How much needs to be drained out and replaced with pure antifreeze to obtaina a 60% antifreeze solution? \n" ); document.write( "

Algebra.Com's Answer #132587 by Mathtut(3670) $\"\"$ $\"About$

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document.write( "amount of pure antifreeze   pure antifreeze to + pure antifreeze = pure antifre\r\n" );
document.write( "in original solution      - be drained out       added             in final sol.\r\n" );
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document.write( "Let x represent the amount of antifreeze to be added\r\n" );
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document.write( ".5(16)-.5(x)+x=.6(16)\r\n" );
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document.write( "8-.5x+x=9.6\r\n" );
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document.write( ".5x=1.6\r\n" );
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document.write( "gallons of pure antifreeze\r\n" );
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