document.write( "Question 177562: At a movie theatre, admission tickets are $5 for children and $8 for adults. The receipts for Friday evening were $2500. The next day, there were three times as many children as the preceding evening and only half the number of adults as the night before, yet the receipts were still $2500. Find the number of children who attended Friday evening. \n" ); document.write( "
Algebra.Com's Answer #132577 by stanbon(75887)\"\" \"About 
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At a movie theatre, admission tickets are $5 for children and $8 for adults. The receipts for Friday evening were $2500.
\n" ); document.write( "Value Equation: 5c + 8a = 2500
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\n" ); document.write( "\n" ); document.write( "The next day, there were three times as many children as the preceding evening and only half the number of adults as the night before, yet the receipts were still $2500.
\n" ); document.write( "Value Equation: 5(3c) + 8(a/2) = 2500
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\n" ); document.write( "\n" ); document.write( "Find the number of children who attended Friday evening.
\n" ); document.write( "System:
\n" ); document.write( "5c + 8a = 2500
\n" ); document.write( "15c+ 4a = 2500
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\n" ); document.write( "Modify:
\n" ); document.write( "5c + 8a = 2500
\n" ); document.write( "30c+ 8a = 5000
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\n" ); document.write( "Subtract to solve for \"c\":
\n" ); document.write( "25c = 2500
\n" ); document.write( "c = 100 (# of child tickets sold)
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\n" ); document.write( "Substitute into 5c + 8a = 2500 to solve for \"a\":
\n" ); document.write( "5*100 + 8a = 2500
\n" ); document.write( "8a = 2000
\n" ); document.write( "a = 250 (# of adult tickets solf)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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