document.write( "Question 177559: I do not know how to solve this.
\n" ); document.write( "Solve by substitution
\n" ); document.write( "x+y=10
\n" ); document.write( "y=4x
\n" ); document.write( "

Algebra.Com's Answer #132575 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
x+y=10......eq 1
\n" ); document.write( "y=4x........eq 2
\n" ); document.write( ":
\n" ); document.write( "take y's value of 4x from eq 2 and plug it into eq 1.
\n" ); document.write( ":
\n" ); document.write( "x+(4x)=10
\n" ); document.write( ":
\n" ); document.write( "5x=10
\n" ); document.write( ":
\n" ); document.write( "\"highlight%28x=2%29\"
\n" ); document.write( ":
\n" ); document.write( "now take x's found value and plug it back into either eq 1 or 2. I choose eq 2
\n" ); document.write( ":
\n" ); document.write( "\"highlight%28y=4%282%29=8%29\"
\n" ); document.write( "
\n" );