document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177562>Question 177562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At a movie theatre, admission tickets are $5 for children and $8 for adults. The receipts for Friday evening were $2500. The next day, there were three times as many children as the preceding evening and only half the number of adults as the night before, yet the receipts were still $2500. Find the number of children who attended Friday evening.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132574 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let c and a be the number of children and adult tickets sold, respectively<BR>\n" );
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document.write( "5c+8a=2500.....eq 1<BR>\n" );
document.write( "5(3c)+8(a/2)=2500....eq 2--->15c+4a=2500<BR>\n" );
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document.write( "5c+8a=2500.....eq 1<BR>\n" );
document.write( "15c+4a=2500....eq 2<BR>\n" );
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document.write( "multiply eq 2 by -2 and add the two equations together thus eliminating the a terms. We are left with -30c+5c=-5000+2500<BR>\n" );
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document.write( "-25c=-2500<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28c=100%29 ALIGN=MIDDLE  ALT=\"highlight%28c=100%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >children attended friday evening </SPAN>\n" );
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