document.write( "Question 177517This question is from textbook Precalculus graphs and models
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document.write( ": the problem is:
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document.write( " log base of 2 times (x+20) minus log base of 2 times (x+2) is equal to log base of 2 x.\r
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document.write( "this is how far i have gotten:
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document.write( "log base of 2 times (x+20/x+2) is equal to log base of 2 x \n" );
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Algebra.Com's Answer #132538 by Electrified_Levi(103)![]() ![]() ![]() You can put this solution on YOUR website! Hi, Hope I can help \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You are correct \n" ); document.write( ". \n" ); document.write( "If you subtract the same number log by the log, it is the same as one complete log as a fraction/division \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This is where you got stuck, from here we can use a really easy method called \"undo\" \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Since this equation has the same base/log (2) on both sides, we can just \"undo\" , get rid of, erase, cross out the logs \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now just solve for \"x\" \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We will now move \"x + 20\" to the right side \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "To find the factors, we have to have multiples of \"-20\", and the multiples have to add up to the middle term, or \"1\" \n" ); document.write( ". \n" ); document.write( "Factors of (-20) \n" ); document.write( ". \n" ); document.write( "(2,(-10)) No \n" ); document.write( ". \n" ); document.write( "(4,(-5)) No \n" ); document.write( ". \n" ); document.write( "(5,(-4)) Yes, \n" ); document.write( ". \n" ); document.write( "Since there was only \n" ); document.write( ". \n" ); document.write( "(x)(x), you would then put the factors inside \n" ); document.write( ". \n" ); document.write( "(x+5)(x-4) are the factors, you can check using the foil method, but I already checked \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "These are your answers, but, you have to make sure and plug your answers into the original equation, and make sure that the numbers don't make a negative, because you can't take the log of a negative number \n" ); document.write( ". \n" ); document.write( "(-5), \n" ); document.write( ". \n" ); document.write( "(4), \n" ); document.write( ". \n" ); document.write( "Here is the graph of the equation \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Remember though that you cannot take the log of a negative, your only answer is \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Hope I helped, Levi \n" ); document.write( " |