document.write( "Question 177517This question is from textbook Precalculus graphs and models
\n" ); document.write( ": the problem is:
\n" ); document.write( " log base of 2 times (x+20) minus log base of 2 times (x+2) is equal to log base of 2 x.\r
\n" ); document.write( "\n" ); document.write( "this is how far i have gotten:
\n" ); document.write( "log base of 2 times (x+20/x+2) is equal to log base of 2 x
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Algebra.Com's Answer #132538 by Electrified_Levi(103)\"\" \"About 
You can put this solution on YOUR website!
Hi, Hope I can help
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\n" ); document.write( "\"+log+%282%2C%28x%2B20%29%29-+log+%282%2C%28x%2B2%29%29+=+log+%282%2Cx%29+\"
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\n" ); document.write( "You are correct
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\n" ); document.write( "If you subtract the same number log by the log, it is the same as one complete log as a fraction/division
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\n" ); document.write( "\"+log+%282%2C%28%28x%2B20%29%2F%28x%2B2%29%29%29+=+log+%282%2Cx%29+\"
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\n" ); document.write( "This is where you got stuck, from here we can use a really easy method called \"undo\"
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\n" ); document.write( "\"+log+%282%2C%28%28x%2B20%29%2F%28x%2B2%29%29%29+=+log+%282%2Cx%29+\"
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\n" ); document.write( "Since this equation has the same base/log (2) on both sides, we can just \"undo\" , get rid of, erase, cross out the logs
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\n" ); document.write( " \"+log+%282%2C%28%28x%2B20%29%2F%28x%2B2%29%29%29+=+log+%282%2Cx%29+\" = \"+%28x%2B20%29%2F%28x%2B2%29+=+x+\"
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\n" ); document.write( "Now just solve for \"x\"
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\n" ); document.write( "\"+%28x%2B20%29%2F%28x%2B2%29+=+x+\", we will multiply each side by (x+2) to get rid of the fraction
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\n" ); document.write( "\"+%28x%2B20%29%2F%28x%2B2%29+=+x+\" = \"+%28x%2B2%29%28%28x%2B20%29%2F%28x%2B2%29%29+=+x%28x%2B2%29+\" = \"+highlight%28x%2B2%29%28%28x%2B20%29%2Fhighlight%28x%2B2%29%29+=+x%28x%2B2%29+\" = \"+cross%28x%2B2%29%28%28x%2B20%29%2Fcross%28x%2B2%29%29+=+x%28x%2B2%29+\" = \"+x%2B20+=+x%28x%2B2%29+\", we will use distribution on the right side
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\n" ); document.write( "\"+x%2B20+=+x%28x%2B2%29+\" = \"+x%2B20+=+highlight%28x%29%28highlight%28x%29%2B2%29+\" = \"+x%2B20+=+highlight%28x%29%28x%2Bhighlight%282%29%29+\" = \"+x+%2B+20+=+x%5E2+%2B+2x+\"
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\n" ); document.write( "We will now move \"x + 20\" to the right side
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\n" ); document.write( "\"+x+%2B+20+=+x%5E2+%2B+2x+\" = \"+x+-+x+%2B+20+-+20=+x%5E2+%2B+2x+-+x+-+20+\" = \"+0+=+x%5E2+%2B+x+-+20+\"
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\n" ); document.write( "\"+0+=+x%5E2+%2B+x+-+20+\" or \"+x%5E2+%2B+x+-+20++=+0\", this is a quadratic equation, we can solve this equation by factoring
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\n" ); document.write( "\"+x%5E2+%2B+x+-+20++=+0\"
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\n" ); document.write( "To find the factors, we have to have multiples of \"-20\", and the multiples have to add up to the middle term, or \"1\"
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\n" ); document.write( "Factors of (-20)
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\n" ); document.write( "(2,(-10)) No
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\n" ); document.write( "(4,(-5)) No
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\n" ); document.write( "(5,(-4)) Yes, \"+5+%2B+%28-4%29+=+1+\" (these factors add up to \"1\")
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\n" ); document.write( "Since there was only \"+x%5E2+\", that means there are only \"x's\"
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\n" ); document.write( "(x)(x), you would then put the factors inside
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\n" ); document.write( "(x+5)(x-4) are the factors, you can check using the foil method, but I already checked
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\n" ); document.write( "\"+%28x%2B5%29%28x-4%29+=+0+\", now we can solve for \"x\", you can find \"x\" by putting each factor equal to zero
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\n" ); document.write( "\"+x+%2B+5+=+0+\", now move \"5\" to the right side
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\n" ); document.write( "\"+x+%2B+5+-+5+=+0+-+5+\" = \"+x+=+%28-5%29+\"
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\n" ); document.write( "\"+x+-+4+=+0+\", now move (-4) to the right side
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\n" ); document.write( "\"+x+-+4+%2B+4+=+0+%2B+4+\" = \"+x+=+4+\"
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\n" ); document.write( "\"+x+=+%28-5%29+\"
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\n" ); document.write( "\"+x+=+4+\"
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\n" ); document.write( "These are your answers, but, you have to make sure and plug your answers into the original equation, and make sure that the numbers don't make a negative, because you can't take the log of a negative number
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\n" ); document.write( "(-5), , we don't have to go any further, since we already found a negative, (-5) will not work
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\n" ); document.write( "(4), \"+log+%282%2C%284%2B20%29%29-+log+%282%2C%284%2B2%29%29+=+log+%282%2C4%29+\" = \"+log+%282%2C24%29-+log+%282%2C%286%29%29+=+log+%282%2C4%29+\", there are no negatives, \"4\" will work
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\n" ); document.write( "Here is the graph of the equation
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\n" ); document.write( "Remember though that you cannot take the log of a negative, your only answer is
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\n" ); document.write( "\"+x+=+4+\"
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\n" ); document.write( "Hope I helped, Levi
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