document.write( "Question 177517This question is from textbook Precalculus graphs and models
\n" ); document.write( ": the problem is:
\n" ); document.write( " log base of 2 times (x+20) minus log base of 2 times (x+2) is equal to log base of 2 x.\r
\n" ); document.write( "\n" ); document.write( "this is how far i have gotten:
\n" ); document.write( "log base of 2 times (x+20/x+2) is equal to log base of 2 x \n" ); document.write( "
Algebra.Com's Answer #132534 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log base of 2 times (x+20) minus log base of 2 times (x+2) is equal to log base of 2 x
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\n" ); document.write( "log(base2)(x+20) - log(base2)(x+2) = log(base2)x
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\n" ); document.write( "It's all base 2 so just keep that in mind:
\n" ); document.write( "log(x+20) - log(x+2) = log2
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\n" ); document.write( "since logA - logB = log(A/B) you get:\r
\n" ); document.write( "\n" ); document.write( "log[(x+20)/(x+2)] = log2\r
\n" ); document.write( "\n" ); document.write( "Taking the inverse log you get:
\n" ); document.write( "(x+20)/(x+2) = 2
\n" ); document.write( "x+20 = 2(x+2)
\n" ); document.write( "x + 20 = 2x + 4
\n" ); document.write( "x = 16
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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