document.write( "Question 177500: Solve for x in log form\r
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document.write( "4^2X-4^X-42=0\r
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document.write( "answer: log(base 4)7 = X \n" );
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Algebra.Com's Answer #132530 by stanbon(75887) ![]() You can put this solution on YOUR website! Solve for x in log form \n" ); document.write( "4^2X-4^X-42=0 \n" ); document.write( "--------- \n" ); document.write( "Let 4^x = w \n" ); document.write( "--------- \n" ); document.write( "Substitute to get: \n" ); document.write( "w^2 - w - 42 = 0 \n" ); document.write( "(w-7)(w+6) = 0 \n" ); document.write( "w = 7 or w = -6 \n" ); document.write( "--------------------- \n" ); document.write( "Substitute to solve for \"x\": \n" ); document.write( "4^x = 7 or 4^x = -6 \n" ); document.write( "No power of 4 can equal -6 so the only solution is that of 4^x=7 \n" ); document.write( "Takethe log of both sides to get: \n" ); document.write( "xlog(4) = log(7) \n" ); document.write( "x = log(7)/log(4) \n" ); document.write( "x = 1.4036775... \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |