document.write( "Question 177495: 4x/5=12/3x
\n" ); document.write( "Solve the proportion.\r
\n" ); document.write( "\n" ); document.write( "My Attempt: 4x*3x=12*5
\n" ); document.write( "12x^2=60
\n" ); document.write( "12x^2/12=60/12
\n" ); document.write( "x^2=5
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #132527 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You're doing great, you just need to take the square root of both sides to get\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%285%29\" or \"x=-sqrt%285%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=sqrt%285%29\" or \"x=-sqrt%285%29\"
\n" ); document.write( "
\n" );