document.write( "Question 177473: The perimeter of one square is 36 inches more than the perimeter of a second square, and the area of the first square is 243 square inches more than the area of the second square. Find the area of the larger square.\r
\n" ); document.write( "\n" ); document.write( "I have tried working this out and I came up with the side of the larger square being x +9,and I don't know if I'm on the right track. I know a perimeter is 4s and area is s^2, but I don't know exactly what to do, and need step by step instructions. Thanks!!!
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Algebra.Com's Answer #132518 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
We know that\"L%5B1%5D\"=\"W%5B1%5D\"} and\"L%5B2%5D\"=\"W%5B2%5D\"}
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\n" ); document.write( "so \"4L%5B1%5D=4L%5B2%5D%2B36\"--->\"L%5B1%5D=L%5B2%5D%2B9\".....eq 1
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\n" ); document.write( "and for the area we know:
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\n" ); document.write( "\"L%5B1%5D%5E2=L%5B2%5D%5E2%2B243\"....eq 2
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\n" ); document.write( "so now lets plug \"L%5B1%5D\"'s value from eq 1 into eq 2
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\n" ); document.write( "\"%28L%5B2%5D%2B9%29%5E2=L%5B2%5D%5E2%2B243\"
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\n" ); document.write( "\"L%5B2%5D%5E2%2B18L%5B2%5D%2B81=L%5B2%5D%2B243\"
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\n" ); document.write( "\"18L%5B2%5D=162\"
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\n" ); document.write( "\"highlight%28L%5B2%5D=9%29\"inches
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\n" ); document.write( "\"highlight%28L%5B1%5D%29=L%5B2%5D%2B9=9%2B9=highlight%2818%29\"inches
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\n" ); document.write( "\"highlight%2818%2A18=324%29\" sq inches for large square
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