document.write( "Question 177448: ln (sqrt x-8)=5\r
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\n" ); document.write( "\n" ); document.write( "ln x + ln (x+3)= 1\r
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\n" ); document.write( "\n" ); document.write( "log (x-6)= log (2x+1)\r
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\n" ); document.write( "\n" ); document.write( "need step by step instructions on how to do each problem... please include answer as well. Thank you.
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Algebra.Com's Answer #132515 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
1. \"ln%28sqrt%28x+-8%29%29=5\"\r
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\n" ); document.write( "\n" ); document.write( "First note that \"sqrt%28a%29+=+a%5E%281%2F2%29\", so: \"ln%28%28x+-8%29%5E%281%2F2%29%29=5\"\r
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\n" ); document.write( "\n" ); document.write( "Now use the rule that \"log%28b%2C%28a%5En%29%29+=+n%2Alog%28b%2C%28a%29%29\" for any \"n\", any \"a%3E0\", and any \"b%3E0\", so: \"%281%2F2%29ln%28x-8%29+=+5\"\"ln%28x+-8%29+=+10\"\r
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\n" ); document.write( "\n" ); document.write( "Now use the definition \"log%28b%2C%28x%29%29+=+y\" if and only if \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "So: \"e%5E10+=+x+-+8\"\"x+=+e%5E10+%2B+8\", which is the exact answer. Use your calculator to get a numerical approximation if that is what you need.\r
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\n" ); document.write( "\n" ); document.write( "\"+ln%28x%29+%2B+ln%28x+%2B+3%29+=+1+\"\r
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\n" ); document.write( "\n" ); document.write( "First use the rule: The sum of the logs equals the log of the product, , so: \"ln%28x%29+%2B+ln%28x+%2B+3%29+=+ln%28x%28x%2B3%29%29+=+ln%28x%5E2+%2B+3x%29+=+1\".\r
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\n" ); document.write( "\n" ); document.write( "Now use the definition \"log%28b%2C%28x%29%29+=+y\" if and only if \"b%5Ey=x\", so:\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28x%5E2+%2B+3x%29+=+1\"\"e%5E1+=+e+=+x%5E2+%2B+3x\"\"x%5E2+%2B+3x+-+e+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Use the quadratic formula: \"x+=+%28-3+%2B-+sqrt%28+3%5E2-4%281%29%28-e%29+%29%29%2F2%281%29+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-3+%2B-+sqrt%28+9%2B4e+%29%29%2F2+\" Again, if you need a numerical approximation, use your calculator.\r
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\n" ); document.write( "\n" ); document.write( "Use the rule: \"log%28b%2C%28a%29%29+=+log%28b%2C+%28c%29%29\" if and only if \"a+=+c\"\r
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\n" ); document.write( "\n" ); document.write( "So: \"x+-+6+=+2x+%2B+1\". You should be able to handle the rest of this one on your own.
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